Can you prove 1=2,well I can.Look inside the debate-Pure Mathematics
We have to prove 1=2:
well let us take a=b where a not= 0 & b not=0
now
ab=b(power 2) [ As, a=b]
so, ab- a(power 2)=b(power 2)-a(power 2)
so after cancellation and applying the formula: b(power 2)-a(power 2)=(b+a)(b-a) and taking the common variable "a" out in L.H.S we have
a=b+a
a=a+a [As a=b]
a=2a
so, 1=2
It's a trick
Can anyone point the mistake?
Can YOU!
3
points
a=b, no zero values, fine. ab=b^2, fine. ab-a^2=b^2-a^2, fine. b^2-a^2=(b+a)(b-a), fine. a=b+a, not fine. To remove the (b-a) from the righthand side of the equation, you would need to divide both sides by (b-a). As it is already established that a=b, this involves division by zero. Further, even if the operation WERE valid, the lefthand side would be (b^2-a^2)/(b-a) = [(b+a)(b-a)]/(b-a), which would eventually (again, ignoring the invalid operation) reduce to (b+a) = (b+a). 1
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