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Debate Score:10
Arguments:16
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 Can you prove 1=2,well I can.Look inside the debate-Pure Mathematics (7)

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Amritangshu(892) pic



Can you prove 1=2,well I can.Look inside the debate-Pure Mathematics

We have to prove 1=2: well let us take a=b where a not= 0 & b not=0 now ab=b(power 2) [ As, a=b] so, ab- a(power 2)=b(power 2)-a(power 2) so after cancellation and applying the formula: b(power 2)-a(power 2)=(b+a)(b-a) and taking the common variable "a" out in L.H.S we have a=b+a a=a+a [As a=b] a=2a so, 1=2 It's a trick Can anyone point the mistake? Can YOU!
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a=b, no zero values, fine.

ab=b^2, fine.

ab-a^2=b^2-a^2, fine.

b^2-a^2=(b+a)(b-a), fine.

a=b+a, not fine. To remove the (b-a) from the righthand side of the equation, you would need to divide both sides by (b-a). As it is already established that a=b, this involves division by zero. Further, even if the operation WERE valid, the lefthand side would be (b^2-a^2)/(b-a) = [(b+a)(b-a)]/(b-a), which would eventually (again, ignoring the invalid operation) reduce to (b+a) = (b+a).

Well let's see brainy if you can solve my other one "the brain teaser",however for this one yeah you and JustIgnoreMe deserves the acclaim

1 point

same thing here?

1-1=0

1(1-1)=0

therefore 1=0 and 0=0

can be done with any value.

you lose half the solution when you take out and divide by the factor. i think you did the same thing (L.H.S? not sure what that refers to)

2 points

1(1-1)=0

therefore 1=0 and 0=0

Incorrect. Therefore either 1=0 OR 0=0

L.H.S

Left hand side of the equation

1 point

that is beyond petty, but thank you for clarifying L.H.S .

thousandin1(1931) Clarified
1 point

1(1-1)=0, fair enough.

But you can't reduce that to 1=0 through any legitimate operation I'm aware of.

Nomoturtle(857) Clarified
1 point

its by the same process by which you solve a quadratic equation. .

Nice to see everyone pointing to the mistake it's a trick and you've to use your brains